Find the product of the terms 2x2y2, 3y2z and –z2x3
Step 1 : 2x2y2, 3y2z and –z2x3 (Given Question)
Step 2 : 2x2y2 x 3y2z x –z2x3 (Multiplication sign used in-between the expressions)
Step 3 : (+) (+) (-) x (2 x 3 x 1) (x2y2) (y2z) (z2x3). (Separated by signs first +,+,-, next separated by numbers 2x3x1, last separated by algebraic expressions)
Step 4 : 6 x2 x3 x y2 y2 X z x z2 (Multiply the signs first, here we will get +x+x- = -, next multiply the numbers, here we will get 2 x 3 x 1 = 6); last multiply combined algebraic expressions by using the exponent law or formula)
Step 5 : - 6 x5 y4 z3 (Using Exponent formula, we will get x2 x x3 = x2+3 = x2 ; y2 x y2 = y2+2 = y4; z x z2 = z1+2 = z3)
Step 6 : Therefore - 6 x5 y4 z3 is an answer.
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